 Oor1 
                                                18.11.2020 22:07
                                                
                                                Oor1 
                                                18.11.2020 22:07
                                             samsamokruxa 
                                                18.11.2020 22:06
                                                
                                                samsamokruxa 
                                                18.11.2020 22:06
                                             tskripko 
                                                18.11.2020 22:06
                                                
                                                tskripko 
                                                18.11.2020 22:06
                                             HupiTip 
                                                18.11.2020 22:06
                                                
                                                HupiTip 
                                                18.11.2020 22:06
                                             temik2005ap08ttx 
                                                18.11.2020 22:06
                                                
                                                temik2005ap08ttx 
                                                18.11.2020 22:06
                                             SKARP17868 
                                                18.11.2020 22:06
                                                
                                                SKARP17868 
                                                18.11.2020 22:06
                                            
<BCH = 90 - <B , <A = 90 - <B => <BCH = <A
cos<BCH = CH/CB = 2/5 = 0,4