Вариант №2 1) 3(x-3) = 4x+
2)4(x-3) = x+ 3;
3) 2*(x- 3) = -3*
4) (x+3)*4 = (x - 9) *
5) 2x-5 = 8 - 3*
6) 5x/3 = (2 -
7) (5x+7)/8 - (3x
8) (5x -1)/3 - (6x
9) (3х - 2)/4 + (2
10) (2x - 4)/5 +

ТигранГеворг    2   18.01.2021 21:49    0