Сократить дробь 1\х+3+3\х-2-х^2+5х+2\х^2+2х-3

=4/x-2-x^2+7x+2/x^2=(4-2x)/x-x^2+7x+2/x^2=(4-2x-x^3)/x+7x+2/x^2=
(4-2x-x^3+7x^2)/x+2/x^2=(4x^2-2x^3-x^5+7x^4+2x)/x^3=(-x^5+7x^4-2x^3+4x^2+2x)/x^3=(-x^4+7x^3-2x^2+4x+2)/x^2