Решите уравнения различными . -24=-2y²+2y 9y²-12y-5=0

(3p-5)(p+1)=-4

3x(x-2)=24

m(m+10)=2

Legendplay228 Legendplay228    1   25.11.2021 13:15    0

Ответы
сартоваа сартоваа  28.12.2021 22:45

- 24 = - 2y² + 2y

12 = y² - y

12 - y² + y = 0

- 12 + y² - y = 0

y² - y - 12 = 0

y² + 3y - 4y - 12 = 0

y × ( y + 3 ) - 4( y + 3 ) = 0

( y + 3 ) × ( y - 4 ) = 0

y + 3 = 0

y - 4 = 0

y = - 3

y = 4

y_{1} = - 3,y_2 = 4

______________________________

9y² - 12y - 5 = 0

9y² + 3y - 15y - 5 = 0

3y × ( 3y + 1 ) - 5(3y + 1 ) = 0

( 3y + 1 ) × ( 3y - 5 ) = 0

3y + 1 = 0

3y - 5 = 0

y = - \frac{1}{3} \\ y = \frac{5}{3}

y _{1} = \frac{1}{3} ,y_2 = \frac{5}{3}

______________________________

( 3p - 5 )( p + 1 ) = - 4

3p² + 3p - 5p - 5 = - 4

3p² - 2p - 5 = - 4

3p² - 2p - 5 + 4 = 0

3p² + p - 3p - 1 = 0

p × ( 3p + 1 ) - ( 3p + 1 ) = 0

( 3p + 1 ) × ( p - 1 ) = 0

3p + 1 = 0

p - 1 = 0

p = - \frac{1}{3} \\

p = 1

p _{1} = - \frac{1}{3} ,p _{2} = 1

______________________________

3x( x - 2 ) = 24

x × ( x - 2 ) = 8

x² - 2x = 8

x² - 2x - 8 = 0

x² + 2x - 4x - 8 = 0

x × ( x + 2 ) - 4( x + 2 ) = 0

( x + 2 ) × ( x - 4 ) = 0

x + 2 = 0

x - 4 = 0

x = - 2

x = 4

x _{1} = - 2,x_2 = 4

______________________________

m(m+10)=2

m² + 10m = 0

m² + 10m - 2 = 0

m = \frac{ - 10 ± \sqrt{10 {}^{2} - 4 \times 1 \times ( - 2) } }{2 \times 1}

m = \frac{ - 10 ± \sqrt{100 + 8} }{2}

m = \frac{ - 10 ± \sqrt{108} }{2}

m= \frac{ - 10 ±6 \sqrt{3} }{2}

m = \frac{ - 10 + 6 \sqrt{3} }{2} \\ m = \frac{ - 10 - 6 \sqrt{3} }{2}

m = - 5 + 3 \sqrt{3} \\ m = - 5 - 3 \sqrt{3}

m _{1} = - 5 - 3 \sqrt{3} ,m_2 = - 5 + 3 \sqrt{3}

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