2)x²-6x+1=0
По Теореме Виета:
x1+x2=6
x1×x2=1
x1+x2+x1x2 =6+1=7
3)x³+3x²y+3xy²+y³=(x+y)³
x+y=-2
(x+y)³=(-2)³
(x+y)³=-8
2)x²-6x+1=0
По Теореме Виета:
x1+x2=6
x1×x2=1
x1+x2+x1x2 =6+1=7
3)x³+3x²y+3xy²+y³=(x+y)³
x+y=-2
(x+y)³=(-2)³
(x+y)³=-8