 StasMe1337 
                                                30.11.2020 20:03
                                                
                                                StasMe1337 
                                                30.11.2020 20:03
                                             rokossovskaya 
                                                30.11.2020 20:04
                                                
                                                rokossovskaya 
                                                30.11.2020 20:04
                                             andreevaa995 
                                                30.11.2020 20:04
                                                
                                                andreevaa995 
                                                30.11.2020 20:04
                                             raizat2004 
                                                30.11.2020 20:04
                                                
                                                raizat2004 
                                                30.11.2020 20:04
                                             tazab705 
                                                30.11.2020 20:04
                                                
                                                tazab705 
                                                30.11.2020 20:04
                                             VikiKot1315 
                                                30.11.2020 20:04
                                                
                                                VikiKot1315 
                                                30.11.2020 20:04
                                             юлия1868 
                                                30.11.2020 20:04
                                                
                                                юлия1868 
                                                30.11.2020 20:04
                                             darka448Darina 
                                                30.11.2020 20:05
                                                
                                                darka448Darina 
                                                30.11.2020 20:05
                                            
Решение
4 5/7х:2 1/13=2 8/9:3 3/11
4(5/7)x * 3(3/11) = 2(1/13) * 2(8/9)
(33*36)*x ]/ (7*33) = [(27*26)/(13*9)]
(36/7)*x = 6
x = 6 : (36/7)
x = 7/6
x = 1(1/6)