Решите,
100-х^2
121а^2
с-8^2
81а^2-72аb-16b^2
oladushek2002oy6bqn
3
10.02.2020 07:09
0
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3
1) 100-х²=(10-х)(10+х)
2) 121а²-25b²=(11a-5b)(11a+5b)
3) (c-8)²=c²-16c+64
4) 81a²-72ab+16b²=(9a-4b)²