f(x0 + Δx) ≈ f(x0) + f'(x0)*Δx
sin 46° = sin (45° + 1°).
x0 = 45°, Δx = 1° = π/180 рад, f'(x) = (sin x)' = cos x
sin 46° ≈ sin 45° + cos(45°) * π/180 = 1/√2 + (1/√2) * π/180 =
= (1 + π/180) / √2 ≈ (1 + 3.14/180) / 1.41 ≈ 0.7216 ≈ 0.72
sin 46° = 0.7193.. ≈ 0.72
Пошаговое объяснение:
f(x0 + Δx) ≈ f(x0) + f'(x0)*Δx
sin 46° = sin (45° + 1°).
x0 = 45°, Δx = 1° = π/180 рад, f'(x) = (sin x)' = cos x
sin 46° ≈ sin 45° + cos(45°) * π/180 = 1/√2 + (1/√2) * π/180 =
= (1 + π/180) / √2 ≈ (1 + 3.14/180) / 1.41 ≈ 0.7216 ≈ 0.72
sin 46° = 0.7193.. ≈ 0.72
Пошаговое объяснение: