(x-x1)/(x2-x1)=(y-y1)(y2-y1)
(x-(-3))/(2-(-3))=(y-6)/(9-6)
(x+3)/5=(y-6)/3
3(x+3)=5(y-6)
3x+9=5y-30
3x-5y+39=0
ответ: 3x-5y+39=0
(x-x1)/(x2-x1)=(y-y1)(y2-y1)
(x-(-3))/(2-(-3))=(y-6)/(9-6)
(x+3)/5=(y-6)/3
3(x+3)=5(y-6)
3x+9=5y-30
3x-5y+39=0
ответ: 3x-5y+39=0