y = C/(5+x) +1
Пошаговое объяснение:
(5+x)dy+(y-1)dx=0
(5+x)dy = - (y-1)dx
dy /(y-1) = - dx /(5+x)
∫dy /(y-1) = - ∫ dx /(5+x)
∫d(y-1) /(y-1) = - ∫ d(5+x) /(5+x)
ln (y-1) = - ln(5+x) +ln C
y -1 = C/(5+x)
y = C/(5+x) +1
Пошаговое объяснение:
(5+x)dy+(y-1)dx=0
(5+x)dy = - (y-1)dx
dy /(y-1) = - dx /(5+x)
∫dy /(y-1) = - ∫ dx /(5+x)
∫d(y-1) /(y-1) = - ∫ d(5+x) /(5+x)
ln (y-1) = - ln(5+x) +ln C
y -1 = C/(5+x)
y = C/(5+x) +1