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1) (3t² - 4t + 2)′=
2) (4x – 0,3x²)′ =
3) (-t³/6 + 8t² - 5)′ =
4) (3sin4x)′ =
5) (-5cos3x)′ =
6) (x²/2 - x³/3 + 7x)′ =
7) (2x + 3)³)′ =
8)(4t³-5t+3) ′=
9) (3x – 0,2x²)′ =
10) (2t² - t³/9 + 8)′ =
11) (7cos6x)′ =
12) (4sin5x)′ =
13) (2x³/3 + x/4 – 8x)′ =
14) ((5x – 4)²)′ =

alenaalefirova    3   05.04.2020 20:22    0