f(x)=(x−3)
3
(x−1)
f
′
(x)=3(x−3)
2
(x−1)+(x−3)
(x)=(x−3)
(3(x−1)+x−3)
(3x−3+x−3)
(4x−6)
(x)=2(x−3)
(2x−3)</var>
\begin{gathered} < var > \\f(x)=(x^2-9)(x+1)\\ f'(x)=2x(x+1)+x^2-9\\ f'(x)=2x^2+2x+x^2-9\\ f'(x)=3x^2+2x-9 < /var > \end{gathered}
<var>
f(x)=(x
−9)(x+1)
(x)=2x(x+1)+x
−9
(x)=2x
+2x+x
(x)=3x
+2x−9</var>
f(x)=(x−3)
3
(x−1)
f
′
(x)=3(x−3)
2
(x−1)+(x−3)
3
f
′
(x)=(x−3)
2
(3(x−1)+x−3)
f
′
(x)=(x−3)
2
(3x−3+x−3)
f
′
(x)=(x−3)
2
(4x−6)
f
′
(x)=2(x−3)
2
(2x−3)</var>
\begin{gathered} < var > \\f(x)=(x^2-9)(x+1)\\ f'(x)=2x(x+1)+x^2-9\\ f'(x)=2x^2+2x+x^2-9\\ f'(x)=3x^2+2x-9 < /var > \end{gathered}
<var>
f(x)=(x
2
−9)(x+1)
f
′
(x)=2x(x+1)+x
2
−9
f
′
(x)=2x
2
+2x+x
2
−9
f
′
(x)=3x
2
+2x−9</var>