835. 1) |x +1,7|×(2x + 3) = 0; 2) |x - 4|× (2x + 7) = 0;3)5х-8|×(x-6) = 0.

Question

Математика: 835. 1) |x +1,7|×(2x + 3) = 0; 2) |x - 4|× (2x + 7) = 0;3)5х-8|×(x-6) = 0.

Алексей08032005 · Answer

1) Ix+1.7|×(2x+3)=0 Ix+1.7|=0 2x+3=0 x1 = -1.7 x2 = -1.5 2) |x - 4|× (2x + 7) = 0 |x - 4|= 02x + 7 = 0х1 = 4х2 = -3,53) |5х-8|×(x-6) = 0|5х-8| = 0(x-6) = 0х1 = 1,6х2 = 6...

835. 1) |x +1,7|×(2x + 3) = 0; 2) |x - 4|× (2x + 7) = 0;
3)5х-8|×(x-6) = 0.

Популярные вопросы