m(CuSO4) = 70 g
m(Cu(OH)2) - ?
n(CuSO4) = 70 / 160 = 0.4375 mol
0.4375 mol x mol
CuSO4 + 2NaOH = Cu(OH)2 + Na2SO4
1 mol 1 mol
1:0.4375 = 1:x
x = 0.4375
m(Cu(OH)2) = 0.4375 * 98 = 42.875 g
ответ: 42.875 g .
m(CuSO4) = 70 g
m(Cu(OH)2) - ?
n(CuSO4) = 70 / 160 = 0.4375 mol
0.4375 mol x mol
CuSO4 + 2NaOH = Cu(OH)2 + Na2SO4
1 mol 1 mol
1:0.4375 = 1:x
x = 0.4375
m(Cu(OH)2) = 0.4375 * 98 = 42.875 g
ответ: 42.875 g .