V(р-ну) = 300 ml
W(NaOH) = 20%
P(р-ну) = 1.23 g / ml
m(NaOH) - ?
m(H2O) - ?
m(р-ну) = 300 * 1.23 = 369 g
m(NaOH) = 0.2 * 369 = 73.8 g
m(H2O) = 369 - 73.8 = 295.2 g
V(р-ну) = 300 ml
W(NaOH) = 20%
P(р-ну) = 1.23 g / ml
m(NaOH) - ?
m(H2O) - ?
m(р-ну) = 300 * 1.23 = 369 g
m(NaOH) = 0.2 * 369 = 73.8 g
m(H2O) = 369 - 73.8 = 295.2 g