дано
m(CH3COOH) = 24 g
+Ca
V(H2) - ?
2CH3COOH+Ca-->(CH3COO)2Ca+H2
M(CH3COOH) = 60 g/mol
n(CH3COOH) = m/M = 24 / 60 = 0.4 mol
2n(CH3COOH) = n(H2)
n(H2) = 0.4 / 2 = 0.2 mol
V(H2) = n*Vm = 0.2 * 22.4 = 4.48 L
ответ 4.48 л
Объяснение:
дано
m(CH3COOH) = 24 g
+Ca
V(H2) - ?
2CH3COOH+Ca-->(CH3COO)2Ca+H2
M(CH3COOH) = 60 g/mol
n(CH3COOH) = m/M = 24 / 60 = 0.4 mol
2n(CH3COOH) = n(H2)
n(H2) = 0.4 / 2 = 0.2 mol
V(H2) = n*Vm = 0.2 * 22.4 = 4.48 L
ответ 4.48 л
Объяснение: