дано
m(Na) - 18.4 g
V(H2) - ?
2CH3COOH+2Na-->2CH3COONa+H2
M(Na) = 23 g/mol
n(Na) = m/M =18.4 / 23 = 0.8 mol
2n(Na) = n(H2)
n(H2) = 0.8 * 1 / 2 = 0.4mol
V(H2) = n(H2)*Vm = 0.4 * 22.4 = 8.96 L
ответ 8.96 л
Объяснение:
дано
m(Na) - 18.4 g
V(H2) - ?
2CH3COOH+2Na-->2CH3COONa+H2
M(Na) = 23 g/mol
n(Na) = m/M =18.4 / 23 = 0.8 mol
2n(Na) = n(H2)
n(H2) = 0.8 * 1 / 2 = 0.4mol
V(H2) = n(H2)*Vm = 0.4 * 22.4 = 8.96 L
ответ 8.96 л
Объяснение: