m(H2SO4) = 9.8 g
m(BaSO4) - ?
n(H2SO4) = 9.8 / 98 = 0.1 mol
0.1 mol x mol
BaCl2 + H2SO4 = BaSO4 + 2HCl
1 mol 1 mol
1:0.1 = 1:x
x = 0.1
m(BaSO4) = 0.1 * 233 = 23.3 g
ответ: m(BaSO4) = 23.3 g.
m(H2SO4) = 9.8 g
m(BaSO4) - ?
n(H2SO4) = 9.8 / 98 = 0.1 mol
0.1 mol x mol
BaCl2 + H2SO4 = BaSO4 + 2HCl
1 mol 1 mol
1:0.1 = 1:x
x = 0.1
m(BaSO4) = 0.1 * 233 = 23.3 g
ответ: m(BaSO4) = 23.3 g.