w(Fe)= (56*100%)/296=18.92%
w(Br3)= (240*100%)/296=81.08%
Ar(BaCO3)=137+13+(16*3)=198
w(Ba)=(1*137)/198=0.691*100=69.1
Объяснение:
w(Fe)= (56*100%)/296=18.92%
w(Br3)= (240*100%)/296=81.08%
Ar(BaCO3)=137+13+(16*3)=198
w(Ba)=(1*137)/198=0.691*100=69.1
Объяснение: