Вычислите массовую долю элемента h3po4

Mr(H3PO4)=3+31+16*4=98

W(H)=1*3\98=0.30*100%=3.06

W(P)=31\98=0.3163*100%=31.63

W(O4)=64\98=0.6530*100%=65.30

w(H) = n(H)·Ar(H)·100% / Mr(H3PO4) = 3·1·100% / 98 = 3,06%  

w(P) = n(P)·Ar(P)·100% / Mr(H3PO4) = 1·31·100% / 98 = 31,63%  

w(O) = n(O)·Ar(O)·100% / Mr(H3PO4) = 4·16·100% / 98 = 65,31%

H=3,06%

P=31,63%

O=65,31%