дано
m(Al) = 170 g
m(Al2S3) - ?
2Al+3S-->Al2S3
M(Al) = 27 g/mol
n(Al) = m/M = 170 / 27 = 6.3 mol
2n(Al) = n(Al2S3)
n(Al2S3) = 6,3 / 2 = 3,15 mol
M(Al2S3) = 150 g/mol
m(Al2S3) = n*M = 3.15 * 150 = 472.5 g
ответ 472.5 г
Объяснение:
дано
m(Al) = 170 g
m(Al2S3) - ?
2Al+3S-->Al2S3
M(Al) = 27 g/mol
n(Al) = m/M = 170 / 27 = 6.3 mol
2n(Al) = n(Al2S3)
n(Al2S3) = 6,3 / 2 = 3,15 mol
M(Al2S3) = 150 g/mol
m(Al2S3) = n*M = 3.15 * 150 = 472.5 g
ответ 472.5 г
Объяснение: