дано
W(Cu) = 40 %
W(S) = 20%
W(O) = 40%
CuxSyOz - ?
m(Cu) =40 g, m(S) = 20 g, m(O) = 40 g
Ar(Cu) = 64 g/moL
Ar(S) = 32 g/mol
Ar(O) = 16 g/mol
CuxSyOz = 40 / 64 : 20 / 32 : 40 / 16
CuxSyOz = 0.625 : 0.625 : 2.5 = 1 : 1 : 4
CuSO4
ответ CuSO4
Объяснение:
дано
W(Cu) = 40 %
W(S) = 20%
W(O) = 40%
CuxSyOz - ?
m(Cu) =40 g, m(S) = 20 g, m(O) = 40 g
Ar(Cu) = 64 g/moL
Ar(S) = 32 g/mol
Ar(O) = 16 g/mol
CuxSyOz = 40 / 64 : 20 / 32 : 40 / 16
CuxSyOz = 0.625 : 0.625 : 2.5 = 1 : 1 : 4
CuSO4
ответ CuSO4
Объяснение: