Дано
CxHy
y = 2x - 2
Mr(CxHy) = 40
Решение
Mr(CxHy) = xAr(C) + yAr(H) = 12x + y = 12x + 2x - 2 = 14x - 2 = 40
14x - 2 = 40
14x = 42
x = 3
y = 2 * 3 - 2 = 4
C3H4
ответ: C3H4
Дано
CxHy
y = 2x - 2
Mr(CxHy) = 40
Решение
Mr(CxHy) = xAr(C) + yAr(H) = 12x + y = 12x + 2x - 2 = 14x - 2 = 40
14x - 2 = 40
14x = 42
x = 3
y = 2 * 3 - 2 = 4
C3H4
ответ: C3H4