дано
m(ppa CH3-CH(OH)-CH2-CH2-CH2-CH3) = 150 g
W( CH3-CH(OH)-CH2-CH2-CH2-CH3) = 80%
+Na
V(H2)-?
m(CH3-CH(OH)-CH2-CH2-CH2-CH3) =150*80%/100% = 120 g
2CH3-CH(OH)-CH2-CH2-CH2-CH3 + 2Na -->2CH3-CH(ONa)-CH2-CH2-CH2-CH3 + H2
M(CH3-CH(OH)-CH2-CH2-CH2-CH3) = 102 g/mol
n(CH3-CH(OH)-CH2-CH2-CH2-CH3) = m/M = 120 / 102 = 1.18 mol
n(CH3-CH(OH)-CH2-CH2-CH2-CH3) = n(H2) = 1.18 mol
V(H2) = n*Vm = 1.18 * 22.4 = 26.432 L
ответ 26.432 л
Объяснение:
дано
m(ppa CH3-CH(OH)-CH2-CH2-CH2-CH3) = 150 g
W( CH3-CH(OH)-CH2-CH2-CH2-CH3) = 80%
+Na
V(H2)-?
m(CH3-CH(OH)-CH2-CH2-CH2-CH3) =150*80%/100% = 120 g
2CH3-CH(OH)-CH2-CH2-CH2-CH3 + 2Na -->2CH3-CH(ONa)-CH2-CH2-CH2-CH3 + H2
M(CH3-CH(OH)-CH2-CH2-CH2-CH3) = 102 g/mol
n(CH3-CH(OH)-CH2-CH2-CH2-CH3) = m/M = 120 / 102 = 1.18 mol
n(CH3-CH(OH)-CH2-CH2-CH2-CH3) = n(H2) = 1.18 mol
V(H2) = n*Vm = 1.18 * 22.4 = 26.432 L
ответ 26.432 л
Объяснение: