ЭxBr3x
w(Br) = 89,89
Mr(ЭxBr3x) = 2*267=534
0,8989 = 3х*80/534
х=0,8989*534/240
х = 2
Э2Br6
Ar(Э) = (534-6*80)/2 =(534-480)/2=54/2 = 27
Al2Br6
ЭxBr3x
w(Br) = 89,89
Mr(ЭxBr3x) = 2*267=534
0,8989 = 3х*80/534
х=0,8989*534/240
х = 2
Э2Br6
Ar(Э) = (534-6*80)/2 =(534-480)/2=54/2 = 27
Al2Br6