Составить рио: 1) mg+ch3cooh-> 2) naoh+ch3cooh-> 3) cao+ch3cooh-> 4) na2co3+ch3cooh->

Daney213 Daney213    1   01.04.2019 14:00    1

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dadfxhg dadfxhg  28.05.2020 05:57

Mg+2CH3COOH = (CH3COO)2Mg + H2

Mg+2CH3COO(-) +2H(+) = 2CH3COO(-) + Mg(2+) + H2

Mg  + 2H(+) = Mg(2+) + H2

 

NaOH+CH3COOH = CH3COONa + H2O

Na(+) + OH(-) + CH3COO(-) + H(+) = CH3COO(-) + Na(+) + H2O

OH(-) + H(+) = H2O

 

CaO+2CH3COOH =(CH3COO)2Ca +H2O

CaO+2CH3COO(-) + 2H(+) =2CH3COO(-) +Ca(2+) +H2O

CaO + 2H(+) = Ca(2+) +H2O

 

Na2CO3+2CH3COOH = 2CH3COONa + H2O + CO2

 2Na(+)  +  CO3(2-) + 2CH3COO(-) + 2H(+) = 2CH3COO(-) + 2Na(+) + H2O + CO2 CO3(2-) + 2H(+) =  H2O + CO2
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