Сколько л h выделяется при взаимодействии 900 г 50% раствора соляной кислоты с железом
Ученик28889
3
21.05.2019 14:04
1
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2
138,09 л
Объяснение:
2HCl + Fe = FeCl2 + H2
m(чист НСl) = 900 * 0,5 = 450 г
n(HCl) = 450 / 36,5 = 12,33 моль = 1/2n(H2)
V(H2) = 6,165 * 22,4 = 138,08 дм3 = 138,09 л