m ( KI ) = (2% * 500) / 100 = 10g
2KI + Pb(NO3)2 = PbI2 + 2 KNO3
v( KI) = 10g / 166g/mol = 0.06 mol
v( PbI2 ) = 0.06 / 2 =0.03 mol
m(PbI2) = 0.03 * 461 g /mol = 13.83 g - маса осадка
m ( KI ) = (2% * 500) / 100 = 10g
2KI + Pb(NO3)2 = PbI2 + 2 KNO3
v( KI) = 10g / 166g/mol = 0.06 mol
v( PbI2 ) = 0.06 / 2 =0.03 mol
m(PbI2) = 0.03 * 461 g /mol = 13.83 g - маса осадка