дано
m(CaC2) = 128 g
m(C2H2)-?
CaC2+2H2O-->Ca(OH)2+C2H2
M(CaC2) = 64 g/mol
n(CaC2) = m/M = 128 / 64 = 2 mol
n(CaC2) = n(C2H2)=2 mol
M(C2H2) = 26 g/mol
m(C2H2) = n*M = 2 * 26 = 52 g
ответ 52 г
Объяснение:
дано
m(CaC2) = 128 g
m(C2H2)-?
CaC2+2H2O-->Ca(OH)2+C2H2
M(CaC2) = 64 g/mol
n(CaC2) = m/M = 128 / 64 = 2 mol
n(CaC2) = n(C2H2)=2 mol
M(C2H2) = 26 g/mol
m(C2H2) = n*M = 2 * 26 = 52 g
ответ 52 г
Объяснение: