NH4Cl + NaOH = NH3 + H2O + NaCl
n NH4Cl = n NH3 = 10.7/(35.5+18) = 0.2моль
V NH3 = 0.2*22.4 = 4.48
4/4.48 = 89.29 %
NH4Cl + NaOH = NH3 + H2O + NaCl
n NH4Cl = n NH3 = 10.7/(35.5+18) = 0.2моль
V NH3 = 0.2*22.4 = 4.48
4/4.48 = 89.29 %