2Al+3H2SO4=Al2(SO4)3+3H2 n(Al):n(Al2(SO4)3)=2:1
n(Al2((SO4)3)=100/342=0.29 моль
x:0.29=2:1
x=0.29*2
x=0.58
m(Al)=n*M
m(Al)=0.58*27=15.66 г
Дано:
m(Al2(SO4)3)=100г
Найти: m(Al)
Решение:
M(Al2(SO4)3)=342г/моль
M(Al)=27г/моль
х/27=100/342
х=7,9г
ответ: m(Al)=7,9г
2Al+3H2SO4=Al2(SO4)3+3H2
n(Al):n(Al2(SO4)3)=2:1
n(Al2((SO4)3)=100/342=0.29 моль
x:0.29=2:1
x=0.29*2
x=0.58
m(Al)=n*M
m(Al)=0.58*27=15.66 г