СnH2n+1NH2 + HCl = СnH2n+1NH3Cl n(HCl)= 6,27:22,4=0,3 мольM(СnH2n+1NH3Cl) = 24,45:0,3=81,5 г/моль12n+2n+1+14+3+35,5=81,514n=28n=2C2H5NH2
СnH2n+1NH2 + HCl = СnH2n+1NH3Cl
n(HCl)= 6,27:22,4=0,3 моль
M(СnH2n+1NH3Cl) = 24,45:0,3=81,5 г/моль
12n+2n+1+14+3+35,5=81,5
14n=28
n=2
C2H5NH2