2Li2O2+2H2O=4LiOH+O2
n(Li2O2)=4.6/46=0.1моль
m(LiOH)=0.2*24=4.8г
m(O2)=32*0.05=1.6г
w(LiOH)=4.8/(4.6+125-1.6)*100%=3.75%
2Li2O2+2H2O=4LiOH+O2
n(Li2O2)=4.6/46=0.1моль
m(LiOH)=0.2*24=4.8г
m(O2)=32*0.05=1.6г
w(LiOH)=4.8/(4.6+125-1.6)*100%=3.75%