Объяснение:
1) C(IV)O(II), N(III)H(I), Br(VII)O(II), Al(III)Cl(I), H(I)S(II), P(V)O(II)
2) 4K + O2 = 2K2O
2KClO3 = 2KCl + 3O2
2Li + 2H2O = 2LiOH + H2
2Al + 3H2SO4 = Al2(SO4)3 + 3H2
Fe2O3 + 6HCl = 2FeCl3 + 6H2O
2FeCl2 + Cl2 =2 FeCl3
3) 2Al + 3Cl2 = 2AlCl3
4K + O2 = 2K2O
4P + 5O2 = 2P2O5
3Zn + 2P = Zn3P2
4) Mr(P2O5) = 31*2 + 16*5 = 142
W(P) = Ar(P) *n / Mr(P2O5) *100% = 31*2 / 142 *100% = 44%
W(O) = Ar(O) *n / Mr(P2O5) *100% = 16*5 / 142 *100% = 56%
Объяснение:
1) C(IV)O(II), N(III)H(I), Br(VII)O(II), Al(III)Cl(I), H(I)S(II), P(V)O(II)
2) 4K + O2 = 2K2O
2KClO3 = 2KCl + 3O2
2Li + 2H2O = 2LiOH + H2
2Al + 3H2SO4 = Al2(SO4)3 + 3H2
Fe2O3 + 6HCl = 2FeCl3 + 6H2O
2FeCl2 + Cl2 =2 FeCl3
3) 2Al + 3Cl2 = 2AlCl3
4K + O2 = 2K2O
4P + 5O2 = 2P2O5
3Zn + 2P = Zn3P2
4) Mr(P2O5) = 31*2 + 16*5 = 142
W(P) = Ar(P) *n / Mr(P2O5) *100% = 31*2 / 142 *100% = 44%
W(O) = Ar(O) *n / Mr(P2O5) *100% = 16*5 / 142 *100% = 56%