дано
m(ppaNaCL) = 300 g
W(NaCL) = 0.1
m(NaCL)-?
m(H2O)-?
m(NaCL) = 300*0.1 = 30 g
m(H2O) = 300 - 30 = 270 g
p(H2O) = 1 g/ml
V(H2O) = m(H2O) / p(H2O) = 270 / 1 = 270 mL
ответ 30 г, 270 mL
Объяснение:
дано
m(ppaNaCL) = 300 g
W(NaCL) = 0.1
m(NaCL)-?
m(H2O)-?
m(NaCL) = 300*0.1 = 30 g
m(H2O) = 300 - 30 = 270 g
p(H2O) = 1 g/ml
V(H2O) = m(H2O) / p(H2O) = 270 / 1 = 270 mL
ответ 30 г, 270 mL
Объяснение: