дано
m(CaCO3) = 200 g
η = 75%
V(CO2)-?
CaCO3+2HNO3-->Ca(NO3)2+H2O+CO2
M(CaCO3) = 100 g/mol
n(CaCO3) = m/M = 200 / 100 = 2 mol
Vтеор(CO2) = n*Vm = 2*22.4 = 44.8 L
V( практCO2) = V(CO2) * 75% / 100% = 33.6 L
ответ 33.6 л
дано
m(CaCO3) = 200 g
η = 75%
V(CO2)-?
CaCO3+2HNO3-->Ca(NO3)2+H2O+CO2
M(CaCO3) = 100 g/mol
n(CaCO3) = m/M = 200 / 100 = 2 mol
Vтеор(CO2) = n*Vm = 2*22.4 = 44.8 L
V( практCO2) = V(CO2) * 75% / 100% = 33.6 L
ответ 33.6 л