дано
m(C2H5OH) = 22 g
m(CH3COOH) - ?
C2H5OH+O2 -->CH3COOH+H2O ( бактерии)
M(C2H5OH) = 46 g/mol
n(C2H5OH) = m/M = 22 / 46 = 0.48 mol
n(CH3COOH) = n(C2H5OH) = 0.48 mol
M(CH3COOH) = 60 g/mol
m(CH3COOH) = n*M = 0.48 * 60 = 28,8 g
ответ 28.8 г
Объяснение:
дано
m(C2H5OH) = 22 g
m(CH3COOH) - ?
C2H5OH+O2 -->CH3COOH+H2O ( бактерии)
M(C2H5OH) = 46 g/mol
n(C2H5OH) = m/M = 22 / 46 = 0.48 mol
n(CH3COOH) = n(C2H5OH) = 0.48 mol
M(CH3COOH) = 60 g/mol
m(CH3COOH) = n*M = 0.48 * 60 = 28,8 g
ответ 28.8 г
Объяснение: