Найдите массу 18*10 в 24 степени молекул кислорода
gvarya05
3
02.10.2019 04:10
0
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Дано
N(O2) = 18 * 10^24
Решение
n(O2) = N(O2) / Na = (18 * 10^24) / (6 * 10^23) = 180 / 6 = 30 моль
m(O2) = n(O2)M(O2) = 30 * 32 = 960 г
ответ: 960 г