CaC₂ + 2H₂O -> Ca (OH)₂ + C₂H₂
ω(CaC₂) = 100%-20%=80%
m(CaC₂) = 0,8*400=320 г.
CaC₂+2H₂O -> Ca(OH)₂+C₂H₂
x= 112 л
CaC₂ + 2H₂O -> Ca (OH)₂ + C₂H₂
ω(CaC₂) = 100%-20%=80%
m(CaC₂) = 0,8*400=320 г.
CaC₂+2H₂O -> Ca(OH)₂+C₂H₂
x= 112 л