2NH4Cl + Ca(OH)2 = CaCl2 + 2NH3 + 2H20
n(Ca(OH)2)=m/M=100/74=1.35 моль
n(Ca(OH)2=n(NH3)=1:2=2.7 моль
V(NH3)=n*Vm=2.7*22.4=60.48 л
2NH4Cl + Ca(OH)2 = CaCl2 + 2NH3 + 2H20
n(Ca(OH)2)=m/M=100/74=1.35 моль
n(Ca(OH)2=n(NH3)=1:2=2.7 моль
V(NH3)=n*Vm=2.7*22.4=60.48 л