дано
m(H2) = 20 g
m(H2SO4) =?
H2SO4+Zn-->ZnSO4+H2
M(H2) =2 g/mol
n(H2) = m/M = 20 / 2= 10 mol
n(H2SO4) = n(H2) = 10 mol
M(H2SO4) = 98 g/mol
m(H2SO4) = n*M = 10 *98 = 980 g
ответ 980 г
Объяснение:
дано
m(H2) = 20 g
m(H2SO4) =?
H2SO4+Zn-->ZnSO4+H2
M(H2) =2 g/mol
n(H2) = m/M = 20 / 2= 10 mol
n(H2SO4) = n(H2) = 10 mol
M(H2SO4) = 98 g/mol
m(H2SO4) = n*M = 10 *98 = 980 g
ответ 980 г
Объяснение: