W(H2SO4) = 10%
m(NaOH) = 20 g
m(р-ра) - ?
N(NaOH) = 20 / 40 = 0.5 mol
0.5 mol x mol
2NaOH + H2SO4 = Na2SO4 + 2H2O
2 mol 1 mol
2:0.5 = 1:x
2x = 0.5
x = 0.25
m(H2SO4) = 0.25 * 98 = 24.5 g
m(р-ра) = 24.5 / 0.1 = 245 g
W(H2SO4) = 10%
m(NaOH) = 20 g
m(р-ра) - ?
N(NaOH) = 20 / 40 = 0.5 mol
0.5 mol x mol
2NaOH + H2SO4 = Na2SO4 + 2H2O
2 mol 1 mol
2:0.5 = 1:x
2x = 0.5
x = 0.25
m(H2SO4) = 0.25 * 98 = 24.5 g
m(р-ра) = 24.5 / 0.1 = 245 g