дано
m( ppa Na2S) = 31.2 g
W(Na2S) = 20%
+CuCL2
m(Na2S) = 31.2 * 20% / 100% = 6.24 g
Na2S+CuCL2-->CuS↓+2NaCL
M(Na2S) = 78g/mol
n(Na2S) = m/M = 6.24 / 78 = 0.08 mol
n(Na2S) = n(CuS) = 0.08 mol
M(CuS) = 96 g/mol
m(CuS) = 0.08 * 96 = 7.68 g
ответ 7.68 г
Объяснение:
дано
m( ppa Na2S) = 31.2 g
W(Na2S) = 20%
+CuCL2
m(Na2S) = 31.2 * 20% / 100% = 6.24 g
Na2S+CuCL2-->CuS↓+2NaCL
M(Na2S) = 78g/mol
n(Na2S) = m/M = 6.24 / 78 = 0.08 mol
n(Na2S) = n(CuS) = 0.08 mol
M(CuS) = 96 g/mol
m(CuS) = 0.08 * 96 = 7.68 g
ответ 7.68 г
Объяснение: