m(Na) = 100 g
V(H2) - ?
n(Na) = 100 / 23 = 4.34 mol
4.34 mol x mol
2Na + 2HCl = 2NaCl + H2
2 mol 1 mol
2:4.34 = 1:x
2x = 4.34
x = 2.17
V(H2) = 2.17 * 22.4 = 48.6 l
m(Na) = 100 g
V(H2) - ?
n(Na) = 100 / 23 = 4.34 mol
4.34 mol x mol
2Na + 2HCl = 2NaCl + H2
2 mol 1 mol
2:4.34 = 1:x
2x = 4.34
x = 2.17
V(H2) = 2.17 * 22.4 = 48.6 l