А)обчисліть масову частку(%)гідрогену в молекулі глюкози.
online19
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21.05.2019 11:10
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1
ДаНо:
C6H12O6
Найти: w(H)
W(э) = Ar(э) ∙ n(э)\Mr(в-ва)
Mr(C6H12O6) = 12 ∙ 6+1∙12 +16∙6 = 180
W(H) = 1 ∙ 12\180 = 0,067 или 6,67%
ответ: W(H) = 6,67%