......................
Объяснение:
n(Fe) = Mr(Fe) /Mr = 56/107× 100% =52%
n(O) = 16×3/107 × 10O%=45%
n(H) = 3/ 107×100% =3%
......................
Объяснение:
n(Fe) = Mr(Fe) /Mr = 56/107× 100% =52%
n(O) = 16×3/107 × 10O%=45%
n(H) = 3/ 107×100% =3%