дано
m техн (CaC2) = 130 kg = 130000 g
W(CaC2)= 80%
V(C2H2)-?
m(CaC2) =130*80% /100% = 104 kg
104kg X m3
CaC2+H2O-->C2H2+Ca(OH)2 M(CaC2) = 64 kg/kmol
64 22.4 m3/kmol
X = 104*22.4 / 64 = 36.4 m3
ответ 36.4м3
дано
m техн (CaC2) = 130 kg = 130000 g
W(CaC2)= 80%
V(C2H2)-?
m(CaC2) =130*80% /100% = 104 kg
104kg X m3
CaC2+H2O-->C2H2+Ca(OH)2 M(CaC2) = 64 kg/kmol
64 22.4 m3/kmol
X = 104*22.4 / 64 = 36.4 m3
ответ 36.4м3