Впараллелограмме abcd диагонали пересечены в точке о. к - середина ав. ак=3, ко=4. найти периметр авсd
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07.03.2019 21:11
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ABCD-параллелограмм, AK- середина AB =>AB=2AK=2*3=6
AB=CD=6
AC и BD- диагонали
KO-середина BС(т.к. АС пересекает BD в точке О)
KO=½ BC=½ CD=4 => BC=2 KO
BC=2*4=8
S(ABCD)=6*8=48
ответ: 48