ответ:53,75 и 775√21/42
Объяснение:
1)sinABD=50/62=25/31⇒∠ABD=arcsin(25/31)≈53,75°
2)sin²ABD+cos²ABD=1
1+ctg²ABD=1/sin²ABD
1+(62/AC)²=(31/25)²
(62/AC)²=(31²-25²)/25²=6*56/25²
62/AC=4√21/25
AC=25*62/4√21=775/2√21=775√21/42
ответ:53,75 и 775√21/42
Объяснение:
1)sinABD=50/62=25/31⇒∠ABD=arcsin(25/31)≈53,75°
2)sin²ABD+cos²ABD=1
1+ctg²ABD=1/sin²ABD
1+(62/AC)²=(31/25)²
(62/AC)²=(31²-25²)/25²=6*56/25²
62/AC=4√21/25
AC=25*62/4√21=775/2√21=775√21/42