Проводник массой 5 г и длиной 0.1 м находится в однородном магнитном поле индукция которого 0.3 тл. проводник расположен перпендикулярно линиям индукции. какой должна быть сила тока в проводнике чтобы сила уравновесила силу тяжести действующую на проводник
Саня11671873478
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09.06.2019 23:50
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1
Fa = B L I sin 90 = B L I
Fт =Fa
mg = B L I
I = mg / BL = 0.005*10 / 0.3*0.1 = 1,7 A
ЭТО верное решение
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